Q.
f(z) = ½(z) + 200 × 2^2+1
f(2) = ?
[tex].[/tex]
![]()
f(z) = ½(z) + 200 × 2^2+1
f(2) = ?
[tex].[/tex]
~Answer -! ☆
______________
f(z) = [tex] \tt \frac{1}{2}[/tex](z) + 200 × [tex] {{2}^{2+1}}[/tex]
f(z) = [tex] \tt \frac{1}{2}[/tex](2) + 200 × 2³
f(z) = 1 ÷ 200 × ( 2 × 2 × 2 )
f(z) = 1 ÷ 200 × ( 4 × 2 )
f(z) = 1 ÷ 200 × 8
f(z) = 1 ÷ 1.600
f(z) = 1.601 ✔
[tex]\purple{ \fcolorbox{purple}{black}{ \boxed{ \orange{ \star}{ \bold{\: •\ |\ Zaa\ \times\ Ghost\ |\ •}\orange{\star}}}}} [/tex]
f(z) = 1/2(z) + 200 × 2^2 + 1
f(2) = 1/2(2) + 200 × 2³
f(2) = 1 + 200 × (2 × 2 × 2)
f(2) = 1 + 200 × 8
f(2) = 1 + 1600
f(2) = 1601
[answer.2.content]
